Gravity Lab

Partners: Gavrielle and Christina

Group 3 

Objective Statement:

Our objective was to figure out the force of gravity measured in newtons when different masses measured in kilograms are added to a force sensor.

Our plan:

Our plan was to measure the force of gravity by adding five different weights to a mass hanger in order to calculate the forces in newtons.

Data Analysis:

1. In order to measure the force of gravity, we used the Dual Range Force Censor program via Logger Pro

2. We then added a metal mass hanger to the force sensor, which weighted 50 grams and used the "zero" option to reccaliberate the scale of the sensor.

3. Next we added different weights to the mass hanger and collected the data of the newtons produced. We repeated this step the following masses: 10 g, 20 g, 30 g, 40 g, and 50 g

4. We then converted each weight from grams to kilograms

5. The equation of the data points was Force = (9.1 N/kg)mass + 0.017 N, where 9.1 N/Kg = the gravitational field strength of the Earth and 0.017 N = when the mass is 0 kg

very nice

Data Table:

VM: As the mass increased in kg, the force of gravity in Newtons also increased proportionally

MM: Force = (9.1 N/Kg)Mass + 0.017 N

Slope: For every 1 Kg added, the force of gravity increased by 9.1 N

Y-intercept: When the mass is 0 kg, the force of gravity is 0.017 N. However, the force of gravity should by 0 N but the scale of our data points is close enough already.good

Conclusion/Claims and Evidence:

Weight, or the force of gravity, can be determined by multiplying the given mass of an object by 9.8 N/kg. The difference between mass and weight is that mass is defined as how much stuff is in something, whereas weight is defined as the force of gravity.excellent In this lab, we observed that the almost every other group had similar slopes to ours, which was 9.1 N/Kg. After finding out the average of each slope, we discovered that the earth's gravitational field strength is 9.8 N per every 1 Kg. So no matter where on the earth's surface, the gravitational strength always yields 9.8 N/Kg. So the new equation is Force = (9.8 N/Kg)Mass + 0 N. The y-intercept can be anything close to zero newtons. Light and heavy objects hit the ground at the same time because objects with different masses fall at the same acceleration rate of 9.8 m/s/s. Under the rule of free fall motion, all objects will fall at the same rate of acceleration regardless of their mass. This is because since all objects are within the Earth's gravitational field, they all experience the same amount of force. no not same force that would mean everything weighs the same...  the reason they all fall at same rate, a more massive object has more force on it, which is the same as a less massive object with less force on it...  the more massive object is harder move so it requires more force to move it. 

otherwise, great job!  neat and thorough!  :)

Dueling Buggies Lab (10/8/14)

Partner: Charles Lau
Group 1

Objective Statement:
Our objective was to figure out find out a model which demonstrated at which point two buggy vehicles moving from different directions will meet at. Both buggies moved at different speeds; one moved at a fast constant velocity while the other moved at a slower constant velocity.

Our plan:
1. In order to create the model for our lab, we needed to find the point-intercept equation y=mx+b
2. Our first step was calculating the speeds of both the red buggy - the faster one, and the blue buggy - the slower one
3. We measured out 100 cm on a table and then decided to calculate how long it would take for each each buggy to get across the table from 0 cm to 100 cm.

Data Analysis:
1. We recorded the data of the slow car first. The blue buggy traveled 100 cm in 2.49 seconds
2. Next we recorded the data of the fast car. The red buggy traveled 100 cm in 14.90 seconds.
3. We then calculated the speed of each buggy using the formula speed = distance/time to configure the constant velocities of each car. The blue buggy's slope was 14.90 cm/sec and the red buggy's slope was 40.16 cm/sec  
4. After finding out the slopes of both cars, we proceeded to use our model by setting the red buggy at 0 cm and the blue buggy at 150 cm, which was the given data
5. The equation for the fast red buggy was x = (40.16 cm/sec)t + 0, where t = time and 0 cm = the starting position.excellent!
6. The equation for the slow blue buggy was x = (-14.90 cm/sec)t + 150, where t = time and 150 cm = the starting position. The slope of this equation was negative because the buggy was moving in a negative direction at a slow constant speed.
7. After graphing both equations on a graphing calculator, we discovered that the two buggies intersected at 2.72 seconds when they both reached 109 cm from their opposite starting positions.

Using our Model/Designing a Solution:
With our model, we predicted that the two buggies would meet somewhere between the interval [105 cm, 110 cm] really early into the lab. The fast red buggy's slope was far steeper than the slope of the blue buggy, therefore it would cover more centimeters per second. We also predicted that two buggies would meet somewhere closer to the starting position of the red car rather than near the starting position of the blue one. Our method pretty much synchronized with the data produced, thus we do not believe that it was wrong.  looks great!